I have a data.frame with column headers.

How can I get a specific row from the data.frame as a list (with the column headers as keys for the list)?

Specifically, my data.frame is

A B C 1 5 4.25 4.5 2 3.5 4 2.5 3 3.25 4 4 4 4.25 4.5 2.25 5 1.5 4.5 3

And I want to get a row that's the equivalent of

```
> c(a=5, b=4.25, c=4.5)
a b c
5.0 4.25 4.5
```

```
x[r,]
```

where r is the row you're interested in. Try this, for example:

```
#Add your data
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = c(4.5, 2.5, 4, 2.25, 3 )
),
.Names = c("A", "B", "C"),
class = "data.frame",
row.names = c(NA, -5L)
)
#The vector your result should match
y<-c(A=5, B=4.25, C=4.5)
#Test that the items in the row match the vector you wanted
x[1,]==y
```

This page (from this useful site) has good information on indexing like this.

Logical indexing is very R-ish. Try:

```
x[ x$A ==5 & x$B==4.25 & x$C==4.5 , ]
```

Or:

```
subset( x, A ==5 & B==4.25 & C==4.5 )
```

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